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| | Mathematics V1205x, Calculus IIIS/IVA, Midterm #2 Solutions 1. Suppose F = 2xyi + (x2 + byz)j + y 2 k. A. For what number b does div(F ) = curl(F ) · i? Note that div(F ) = 2y + bz and curl(F ) = (2y − by)i + 0j + 0k.Add to Reading ListSource URL: www.math.columbia.eduDownload Document from Source Website File Size: 71,13 KBShare Document on Facebook
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