Section[removed]i) (−3 i)(14 − 2i) = (−3)(14 − 2i) i(14 − 2i) = {(−3)14 − (−3)(2i)} i(14) − i(2i) - 2I - Document - PDFSEARCH.IO

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	Section[removed]i) (−3 + i)(14 − 2i) = (−3)(14 − 2i) + i(14 − 2i) = {(−3)14 − (−3)(2i)} + i(14) − i(2i) Add to Reading List Document Date: 2001-12-30 01:48:58 Open Document File Size: 104,33 KB Share Result on Facebook Currency pence / cent / / / SocialTag Geometry Complex analysis Analytic geometry Circles Fourier analysis Unit circle Complex number Complex plane Pythagorean trigonometric identity Mathematical analysis

Section[removed]i) (−3 + i)(14 − 2i) = (−3)(14 − 2i) + i(14 − 2i) = {(−3)14 − (−3)(2i)} + i(14) − i(2i)Add to Reading List