Homework 1 Solution – Stat111 summer 2010 • a) The given probabilities have sum 0.41 so P(english)=b) P(not english)=1P(english)=0.41. • 4.32 (a) There are six arrangements of the digits 4,5 and 6 (45 - 4-Digits - Document - PDFSEARCH.IO

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	Homework 1 Solution – Stat111 summer 2010 • a) The given probabilities have sum 0.41 so P(english)=b) P(not english)=1P(english)=0.41. • 4.32 (a) There are six arrangements of the digits 4,5 and 6 (45 Add to Reading List Document Date: 2010-06-02 12:10:13 Open Document File Size: 57,49 KB Share Result on Facebook

Homework 1 Solution – Stat111 summer 2010 • a) The given probabilities have sum 0.41 so P(english)=b) P(not english)=1P(english)=0.41. • 4.32 (a) There are six arrangements of the digits 4,5 and 6 (45Add to Reading List