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Date: 2015-09-03 07:54:06 | ∃y∀x Rx y ⊢ ∀x∃yRx y We want to show that ∃y∀xRx y ⊢ ∀x∃yRx y. ∃y∀x Rx y ⊢ ∀x∃yRx yAdd to Reading ListSource URL: logicmanual.philosophy.ox.ac.ukDownload Document from Source WebsiteFile Size: 163,46 KBShare Document on Facebook |