![](https://www.pdfsearch.io/img/b8fd6f06981ce116d02ac4c9d873aac0.jpg) Date: 2017-11-13 11:53:55
| | Cryptography module, AnswersInitially, we have L0 = 86, R0 = 83, K0 = 89. Then we run the first round, to obtain L1 = 83, R1 = 2. Also, K1 = 164. So, computing the next round, we have L2 = 9 and R2 = 2. So the outAdd to Reading ListSource URL: www.cs.bham.ac.ukDownload Document from Source Website File Size: 100,02 KBShare Document on Facebook
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