501 | Add to Reading ListSource URL: www.philbirnbaum.comLanguage: English - Date: 2003-09-07 23:09:08
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502 | Add to Reading ListSource URL: www.philbirnbaum.comLanguage: English - Date: 2007-12-11 12:18:07
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503 | Add to Reading ListSource URL: www.math.jussieu.frLanguage: English - Date: 2004-09-20 07:25:40
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504 | Add to Reading ListSource URL: www.amaps.orgLanguage: English - Date: 2008-08-03 20:21:44
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505 | Add to Reading ListSource URL: www.philbirnbaum.comLanguage: English - Date: 2004-07-19 19:19:22
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506 | Add to Reading ListSource URL: www.philbirnbaum.comLanguage: English - Date: 2004-10-15 18:57:59
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507![The Math Circle, Spring[removed]Talks by Gordon Ritter) What is Non-Euclidean Geometry? Most geometries on the plane R2 are non-Euclidean. Let s denote arc length. Then Euclidean geometry arises from the formula for curve](https://www.pdfsearch.io/img/e560f63cf97c708bdace66c4d4eade0b.jpg "The Math Circle, Spring[removed]Talks by Gordon Ritter) What is Non-Euclidean Geometry? Most geometries on the plane R2 are non-Euclidean. Let s denote arc length. Then Euclidean geometry arises from the formula for curve") | Add to Reading ListSource URL: www.themathcircle.orgLanguage: English - Date: 2007-02-16 09:21:01
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508![51th Mathematical Olympiad in Poland Problems of the first round, September – December[removed]Let n ≥ 3 be a positive integer. Prove that the sum of the cubes of all natural numbers, coprime and less than n, is divi](https://www.pdfsearch.io/img/2ea56cb7ce8e2086a4a954c6b9e73375.jpg "51th Mathematical Olympiad in Poland Problems of the first round, September – December[removed]Let n ≥ 3 be a positive integer. Prove that the sum of the cubes of all natural numbers, coprime and less than n, is divi") | Add to Reading ListSource URL: www.mimuw.edu.plLanguage: English - Date: 2000-11-24 10:05:48
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509![Section[removed]i) (−3 + i)(14 − 2i) = (−3)(14 − 2i) + i(14 − 2i) = {(−3)14 − (−3)(2i)} + i(14) − i(2i)](https://www.pdfsearch.io/img/647e6af3aa6f3024f6537e8ca028ba6b.jpg "Section[removed]i) (−3 + i)(14 − 2i) = (−3)(14 − 2i) + i(14 − 2i) = {(−3)14 − (−3)(2i)} + i(14) − i(2i)") | Add to Reading ListSource URL: www.numbertheory.orgLanguage: English - Date: 2001-12-30 01:48:58
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510 | Add to Reading ListSource URL: www.chess-math.orgLanguage: English - Date: 2014-05-19 23:44:18
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