Solutions to Selected Exercises 12 1. ||2| − | − 5|| = |2 − 5| = | − 3| = 3. 2. iii If |2 x| = 5 then 2 x = 5 or 2 x = −5. So, x = 3 or x = −7. 3. ii y = |x2 x − 2| The easiest way to draw this grap - Quotient rule - Document - PDFSEARCH.IO

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	Solutions to Selected Exercises 12 1. \|\|2\| − \| − 5\|\| = \|2 − 5\| = \| − 3\| = 3. 2. iii If \|2 + x\| = 5 then 2 + x = 5 or 2 + x = −5. So, x = 3 or x = −7. 3. ii y = \|x2 + x − 2\| The easiest way to draw this grap Add to Reading List Document Date: 2006-08-04 01:52:05 Open Document File Size: 65,78 KB Share Result on Facebook Movie The easiest way / / Organization eln / / SocialTag Integral calculus Mathematical analysis Trigonometry Integration by parts Quotient rule Mathematics Mathematical fallacy Proof theory

Solutions to Selected Exercises 12 1. ||2| − | − 5|| = |2 − 5| = | − 3| = 3. 2. iii If |2 + x| = 5 then 2 + x = 5 or 2 + x = −5. So, x = 3 or x = −7. 3. ii y = |x2 + x − 2| The easiest way to draw this grapAdd to Reading List